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36x^2+35x+6=0
a = 36; b = 35; c = +6;
Δ = b2-4ac
Δ = 352-4·36·6
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-19}{2*36}=\frac{-54}{72} =-3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+19}{2*36}=\frac{-16}{72} =-2/9 $
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